TRIGONOMETRY AND RADIANS

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

QUADRANTS

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

QUESTION 20:

(TRIGONOMETRIC EQUATIONS).

θ = s/60 × 2π

sin^2(θ) + 2 = 11/4

2cos(θ) + 1 = 0

a. Solve for θ.

sin^2(θ) =11/4 - 2 = 3/4

sin(θ) = √(3/4) = √(3)/2

sin^-1(√(3)/2) = π/3

2cos(θ) = - 1

cos(θ) = -1/2

cos^-1(-1/2) = 2π/3

θ = 2π/3

b. Solve for s.

2π/3 = s/60 × 2π

1/3 = s/60

s = 1/3 × 60 = 20

c. Re-divide s by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years then add k + M/(73/6) to get y.

s/60 = 1/3

m = k + s/60 = 49/3

k = m - s/60 = 16

m/60 = 49/180

h = k + m/60 = 3829/180

k = h - m/60 = 21

h/24 = 3829/4320

d = k + h/24 = 68629/4320

k = d - h/24 = 15

d/30 = 68629/129600

M = k + d/30 = 846229/129600

k = M - d/30 = 6

M/(73/6) = 846229/1576800

y = k + M/(73/6) = 103629719029/1576800

k = y - M/(73/6) = 65721

d. Create another angle (θ) from M/(73/6) × 2π and get the sine and cosine. Also although you already know it and the object is defeated, workout θ.

y = sin(M(73/6) × 2π) = 0.05881902090299

x = cos(M(73/6) × 2π) = 0.99826866262545

Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here:

https://8uvp.app.link/FeZPwAXF1V

sin^-1(y) = θ = 846229π/788400

cos^-1(x) = θ = 846229π/788400

e. Although you have already done it workout M/(73/6), M and k.

M/(73/6) = θ/2π = 846229/1576800

M = M/(73/6) × (73/6) = 846229/129600

k = M - d/30 = 6

f. Although you have already done it from (s), workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.

d/30 = M - k = 68629/129600

d = (M - k) × 30 = 68629/4320

k = d - h/24 = 15

h/24 = d - k = 3829/4320

h = (d - k) × 24 = 3829/180

k = h - m/60 = 21

m/60 = h - k = 49/180

m = (h - k) × 60 = 49/3

k = m - s/60 = 16

s/60 = m - k = 1/3

s = (m - k) × 60 = 20

t = 65721 years 6 months 15 days 21:16:20

g. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?

T^1 = √(A/B) = 10^15 fs

T^-1 = √(B/A) = 10^-15 Ps

T^2 = A/B = 10^30 fs²

T^-2 = B/A = 10^-30 Ps²

h. Workout the values of t, A and B?

t = A/T^1 = y × 31536000 = 2.072594380580 × 10^12 s

A = tT^1 = X × 10^12 × 10^15 = X × 10^27 fs

B = A/T^2 = X × 10^27 / 10^30 = X × 10^-3 Ps

i. Check months and days.

y - d/365 = t / 31536000 - d/365 = 65721

d - h/24 = d/365 × 365 - h/24 = 195

h - m/60 = h/24 × 24 - m/60 = 21

m - s/60 = m/60 × 60 - s/60 = 16

s - cs/100 = s/60 × 60 - cs/100 = 20

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 2072594380580 / 31536000 - d/365 = 65721

d - h/24 = (65721.5366749112 - 65721) × 365 - h/24 = 195

h - m/60 = (195.886342592592 - 195) × 24 - m/60 = 21

m - s/60 = (21.2722222222222 - 21) × 60 - s/60 = 16

s - cs/100 = (16.3333333333333 - 16) × 60 - cs/100 = 20

t = 65721 years 195 days 21:16:20

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

QUADRANTS

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

QUESTION 20:

(TRIGONOMETRIC EQUATIONS).

θ = s/60 × 2π

sin^2(θ) + 2 = 11/4

2cos(θ) + 1 = 0

a. Solve for θ.

sin^2(θ) =11/4 - 2 = 3/4

sin(θ) = √(3/4) = √(3)/2

sin^-1(√(3)/2) = π/3

2cos(θ) = - 1

cos(θ) = -1/2

cos^-1(-1/2) = 2π/3

θ = 2π/3

b. Solve for s.

2π/3 = s/60 × 2π

1/3 = s/60

s = 1/3 × 60 = 20

c. Re-divide s by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years then add k + M/(73/6) to get y.

s/60 = 1/3

m = k + s/60 = 49/3

k = m - s/60 = 16

m/60 = 49/180

h = k + m/60 = 3829/180

k = h - m/60 = 21

h/24 = 3829/4320

d = k + h/24 = 68629/4320

k = d - h/24 = 15

d/30 = 68629/129600

M = k + d/30 = 846229/129600

k = M - d/30 = 6

M/(73/6) = 846229/1576800

y = k + M/(73/6) = 103629719029/1576800

k = y - M/(73/6) = 65721

d. Create another angle (θ) from M/(73/6) × 2π and get the sine and cosine. Also although you already know it and the object is defeated, workout θ.

y = sin(M(73/6) × 2π) = 0.05881902090299

x = cos(M(73/6) × 2π) = 0.99826866262545

Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here:

https://8uvp.app.link/FeZPwAXF1V

sin^-1(y) = θ = 846229π/788400

cos^-1(x) = θ = 846229π/788400

e. Although you have already done it workout M/(73/6), M and k.

M/(73/6) = θ/2π = 846229/1576800

M = M/(73/6) × (73/6) = 846229/129600

k = M - d/30 = 6

f. Although you have already done it from (s), workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.

d/30 = M - k = 68629/129600

d = (M - k) × 30 = 68629/4320

k = d - h/24 = 15

h/24 = d - k = 3829/4320

h = (d - k) × 24 = 3829/180

k = h - m/60 = 21

m/60 = h - k = 49/180

m = (h - k) × 60 = 49/3

k = m - s/60 = 16

s/60 = m - k = 1/3

s = (m - k) × 60 = 20

t = 65721 years 6 months 15 days 21:16:20

g. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?

T^1 = √(A/B) = 10^15 fs

T^-1 = √(B/A) = 10^-15 Ps

T^2 = A/B = 10^30 fs²

T^-2 = B/A = 10^-30 Ps²

h. Workout the values of t, A and B?

t = A/T^1 = y × 31536000 = 2.072594380580 × 10^12 s

A = tT^1 = X × 10^12 × 10^15 = X × 10^27 fs

B = A/T^2 = X × 10^27 / 10^30 = X × 10^-3 Ps

i. Check months and days.

y - d/365 = t / 31536000 - d/365 = 65721

d - h/24 = d/365 × 365 - h/24 = 195

h - m/60 = h/24 × 24 - m/60 = 21

m - s/60 = m/60 × 60 - s/60 = 16

s - cs/100 = s/60 × 60 - cs/100 = 20

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 2072594380580 / 31536000 - d/365 = 65721

d - h/24 = (65721.5366749112 - 65721) × 365 - h/24 = 195

h - m/60 = (195.886342592592 - 195) × 24 - m/60 = 21

m - s/60 = (21.2722222222222 - 21) × 60 - s/60 = 16

s - cs/100 = (16.3333333333333 - 16) × 60 - cs/100 = 20

t = 65721 years 195 days 21:16:20

TRIGONOMETRY AND RADIANS
When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.
However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).
For example:
0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.
0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.
0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.
0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.
0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.
0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.
0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.
0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.
0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.
0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.
0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.
However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.
For example:
0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.
0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.
0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.
0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.
0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.
0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.
0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.
0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.
0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.
0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.
0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.
As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).
For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.
QUADRANTS
The following is the formula for attaining θ in the 4 quadrants of the unit circle:
Q1.
sin^-1(y) = θ
cos^-1(x) = θ
Q2.
sin^-1(y) = π - θ therefore θ = π - sin^-1(y)
cos^-1(x) = θ
Q3.
sin^-1(y) = π - θ therefore θ = π - sin^-1(y)
cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)
Q4.
sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)
cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)
QUESTION 20:
(TRIGONOMETRIC EQUATIONS).
θ = s/60 × 2π
sin^2(θ) + 2 = 11/4
2cos(θ) + 1 = 0
a. Solve for θ.
sin^2(θ) =11/4 - 2 = 3/4
sin(θ) = √(3/4) = √(3)/2
sin^-1(√(3)/2) = π/3
2cos(θ) = - 1
cos(θ) = -1/2
cos^-1(-1/2) = 2π/3
θ = 2π/3
b. Solve for s.
2π/3 = s/60 × 2π
1/3 = s/60
s = 1/3 × 60 = 20
c. Re-divide s by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years then add k + M/(73/6) to get y.
s/60 = 1/3
m = k + s/60 = 49/3
k = m - s/60 = 16
m/60 = 49/180
h = k + m/60 = 3829/180
k = h - m/60 = 21
h/24 = 3829/4320
d = k + h/24 = 68629/4320
k = d - h/24 = 15
d/30 = 68629/129600
M = k + d/30 = 846229/129600
k = M - d/30 = 6
M/(73/6) = 846229/1576800
y = k + M/(73/6) = 103629719029/1576800
k = y - M/(73/6) = 65721
d. Create another angle (θ) from M/(73/6) × 2π and get the sine and cosine. Also although you already know it and the object is defeated, workout θ.
y = sin(M(73/6) × 2π) = 0.05881902090299
x = cos(M(73/6) × 2π) = 0.99826866262545
Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here:
https://8uvp.app.link/FeZPwAXF1V
sin^-1(y) = θ = 846229π/788400
cos^-1(x) = θ = 846229π/788400
e. Although you have already done it workout M/(73/6), M and k.
M/(73/6) = θ/2π = 846229/1576800
M = M/(73/6) × (73/6) = 846229/129600
k = M - d/30 = 6
f. Although you have already done it from (s), workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.
d/30 = M - k = 68629/129600
d = (M - k) × 30 = 68629/4320
k = d - h/24 = 15
h/24 = d - k = 3829/4320
h = (d - k) × 24 = 3829/180
k = h - m/60 = 21
m/60 = h - k = 49/180
m = (h - k) × 60 = 49/3
k = m - s/60 = 16
s/60 = m - k = 1/3
s = (m - k) × 60 = 20
t = 65721 years 6 months 15 days 21:16:20
g. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?
T^1 = √(A/B) = 10^15 fs
T^-1 = √(B/A) = 10^-15 Ps
T^2 = A/B = 10^30 fs²
T^-2 = B/A = 10^-30 Ps²
h. Workout the values of t, A and B?
t = A/T^1 = y × 31536000 = 2.072594380580 × 10^12 s
A = tT^1 = X × 10^12 × 10^15 = X × 10^27 fs
B = A/T^2 = X × 10^27 / 10^30 = X × 10^-3 Ps
i. Check months and days.
y - d/365 = t / 31536000 - d/365 = 65721
d - h/24 = d/365 × 365 - h/24 = 195
h - m/60 = h/24 × 24 - m/60 = 21
m - s/60 = m/60 × 60 - s/60 = 16
s - cs/100 = s/60 × 60 - cs/100 = 20
NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.
For example:
Note: you do not need to write the below, it is all done on the calculator.
y - d/365 = 2072594380580 / 31536000 - d/365 = 65721
d - h/24 = (65721.5366749112 - 65721) × 365 - h/24 = 195
h - m/60 = (195.886342592592 - 195) × 24 - m/60 = 21
m - s/60 = (21.2722222222222 - 21) × 60 - s/60 = 16
s - cs/100 = (16.3333333333333 - 16) × 60 - cs/100 = 20
t = 65721 years 195 days 21:16:20

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