• TRIGONOMETRY AND RADIANS

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

QUESTION 21:

(TRIGONOMETRIC EQUATIONS).

θ = s/60 × 2π

2sin^3(θ) = (-3√3)/4

3cos^3(θ) + 6 = 45/8

a. Solve for θ.

sin^3(θ) = (-3√3)/8

sin(θ) = ³√((-3√3)/8) = -√(3)/2

sin^-1(-√(3)/2) = π - θ = -π/3

θ = π - sin^-1(-√(3)/2) = 4π/3

3cos^3(θ) = 45/8 - 6 = -3/8

cos(θ)^3 = -1/8

cos(θ) = ³√(-1/8) = -1/2

cos^-1(-1/2) = 2π - θ = 2π/3

θ = 2π - cos^-1(-1/2) = 4π/3

b. Solve for s.

4π/3 = s/60 × 2π

2/3 = s/60

s = 2/3 × 60 = 40

c. Re-divide s by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years (y) then add k + M/(73/6) to get y.

s/60 = 2/3

k = m - s/60 = 43

m = k + s/60 = 131/3

m/60 = 131/180

k = h - m/60 = 15

h = k + m/60 = 2831/180

h/24 = 2831/4320

k = d - h/24 = 17

d = k + h/24 = 76271/4320

d/30 = 76271/129600

k = M - d/30 = 8

M = k + d/30 = 1113071/129600

M/(73/6) = 1113071/1576800

k = y - M/(73/6) = 11380

y = k + M/(73/6) = 17945097071/1576800

d. Create another angle (θ) from M/(73/6) × 2π and get the sine and cosine. Also although you already know it and the object is defeated, workout θ.

y = sin(M(73/6) × 2π) = -0.96186457013315

x = cos(M(73/6) × 2π) = -0.27352613901153

Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here:

Natural Scientific Calculator (NSC).

sin^-1(y) = π - θ = -324671π/788400

θ = π - sin^-1(y) = 1113071π/1576800

cos^-1(x) = 2π - θ = 463729π/788400

θ = 2π - cos^-1(x) = 1113071π/1576800

e. Although you have already done it workout M/(73/6), M and k.

M/(73/6) = θ/2π = 1113071/1576800

M = M/(73/6) × (73/6) = 1113071/129600

k = M - d/30 = 8

f. Although you have already done it from (s) upwards, reverse-workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.

d/30 = M - k = 76271/129600

d = (M - k) × 30 = 76271/4320

k = d - h/24 = 17

h/24 = d - k = 2831/4320

h = (d - k) × 24 = 2831/180

k = h - m/60 = 15

m/60 = h - k = 131/180

m = (h - k) × 60 = 131/3

k = m - s/60 = 43

s/60 = m - k = 2/3

s = (m - k) × 60 = 40

t = 11380 years 8 months 17 days 15:43:40

g. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?

T^1 = √(A/B) = 10^3 ms

T^-1 = √(B/A) = 10^-3 ks

T^2 = A/B = 10^6 ms²

T^-2 = B/A = 10^-6 ks²

h. Workout the values of t, A and B?

t = A/T^1 = y × 31536000 = 3.58901941420 × 10^11 s

A = tT^1 = X × 10^11 × 10^3 = X × 10^14 ms

B = A/T^2 = X × 10^14 / 10^6 = X × 10^8 ks

i. Check months and days.

y - d/365 = t / 31536000 - d/365 = 11380

d - h/24 = d/365 × 365 - h/24 = 257

h - m/60 = h/24 × 24 - m/60 = 15

m - s/60 = m/60 × 60 - s/60 = 43

s - cs/100 = s/60 × 60 - cs/100 = 40

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 358901941420 / 31536000 - d/365 = 11380

d - h/24 = (11,380.7059049974 - 11380) × 365 - h/24 = 257

h - m/60 = (257.655324074074 - 257) × 24 - m/60 = 15

m - s/60 = (15.7277777777777 - 15) × 60 - s/60 = 43

s - cs/100 = (43.6666666666666 - 43) × 60 - cs/100 = 40

t = 11380 years 257 days 15:43:40
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• TRIGONOMETRY AND RADIANS

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

QUESTION 20:

(TRIGONOMETRIC EQUATIONS).

θ = s/60 × 2π

sin^2(θ) + 2 = 11/4

2cos(θ) + 1 = 0

a. Solve for θ.

sin^2(θ) =11/4 - 2 = 3/4

sin(θ) = √(3/4) = √(3)/2

sin^-1(√(3)/2) = π/3

2cos(θ) = - 1

cos(θ) = -1/2

cos^-1(-1/2) = 2π/3

θ = 2π/3

b. Solve for s.

2π/3 = s/60 × 2π

1/3 = s/60

s = 1/3 × 60 = 20

c. Re-divide s by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years then add k + M/(73/6) to get y.

s/60 = 1/3

m = k + s/60 = 49/3

k = m - s/60 = 16

m/60 = 49/180

h = k + m/60 = 3829/180

k = h - m/60 = 21

h/24 = 3829/4320

d = k + h/24 = 68629/4320

k = d - h/24 = 15

d/30 = 68629/129600

M = k + d/30 = 846229/129600

k = M - d/30 = 6

M/(73/6) = 846229/1576800

y = k + M/(73/6) = 103629719029/1576800

k = y - M/(73/6) = 65721

d. Create another angle (θ) from M/(73/6) × 2π and get the sine and cosine. Also although you already know it and the object is defeated, workout θ.

y = sin(M(73/6) × 2π) = 0.05881902090299

x = cos(M(73/6) × 2π) = 0.99826866262545

Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here:

sin^-1(y) = θ = 846229π/788400

cos^-1(x) = θ = 846229π/788400

e. Although you have already done it workout M/(73/6), M and k.

M/(73/6) = θ/2π = 846229/1576800

M = M/(73/6) × (73/6) = 846229/129600

k = M - d/30 = 6

f. Although you have already done it from (s), workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.

d/30 = M - k = 68629/129600

d = (M - k) × 30 = 68629/4320

k = d - h/24 = 15

h/24 = d - k = 3829/4320

h = (d - k) × 24 = 3829/180

k = h - m/60 = 21

m/60 = h - k = 49/180

m = (h - k) × 60 = 49/3

k = m - s/60 = 16

s/60 = m - k = 1/3

s = (m - k) × 60 = 20

t = 65721 years 6 months 15 days 21:16:20

g. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?

T^1 = √(A/B) = 10^15 fs

T^-1 = √(B/A) = 10^-15 Ps

T^2 = A/B = 10^30 fs²

T^-2 = B/A = 10^-30 Ps²

h. Workout the values of t, A and B?

t = A/T^1 = y × 31536000 = 2.072594380580 × 10^12 s

A = tT^1 = X × 10^12 × 10^15 = X × 10^27 fs

B = A/T^2 = X × 10^27 / 10^30 = X × 10^-3 Ps

i. Check months and days.

y - d/365 = t / 31536000 - d/365 = 65721

d - h/24 = d/365 × 365 - h/24 = 195

h - m/60 = h/24 × 24 - m/60 = 21

m - s/60 = m/60 × 60 - s/60 = 16

s - cs/100 = s/60 × 60 - cs/100 = 20

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 2072594380580 / 31536000 - d/365 = 65721

d - h/24 = (65721.5366749112 - 65721) × 365 - h/24 = 195

h - m/60 = (195.886342592592 - 195) × 24 - m/60 = 21

m - s/60 = (21.2722222222222 - 21) × 60 - s/60 = 16

s - cs/100 = (16.3333333333333 - 16) × 60 - cs/100 = 20

t = 65721 years 195 days 21:16:20
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• TRIGONOMETRY AND RADIANS

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

QUESTION 19:

(CREATE YOUR OWN QUESTIONS).

a. Choose any whole number between 1 and 59 for seconds (s) and divide it by 60 to get s/60. Then choose k for minutes (m) and add k + s/60 to get m. Then divide m by 60 and choose k for hours (h) then add k + m/60 to get h. Then divide h by 24 and choose k for days (d) then add k + h/24 to get d. Then divide d by 30 and choose k for months (M) then add k + d/30 to get M. Then divide M by (73/6) and choose k for years (y) then add k + M/(73/6) to get y.

s/60 = 11/20

m = k + s/60 = 531/20

k = m - s/60 = 26

m/60 = 177/400

h = k + m/60 = 7377/400

k = h - m/60 = 18

h/24 = 2459/3200

d = k + h/24 = 69659/3200

k = d - h/24 = 21

d/30 = 69659/96000

M = k + d/30 = 1029659/96000

k = M - d/30 = 10

M/(73/6) = 1029659/1168000

y = k + M/(73/6) = 67305861659/1168000

k = y - M/(73/6) = 57624

b. Create angle (θ) from M/(73/6) × 2π and get the sine and cosine.

y = sin(M(73/6) × 2π) = -0.67738134317054

x = cos(M(73/6) × 2π) = -0.73563205199642

c. Although you already know it and the object is defeated, workout θ.

Note: to workout nice neat radians fractions instead of ugly decimals you need the Natural Scientific Calculator app! Invite link here: https://8uvp.app.link/FeZPwAXF1V

sin^-1(y) = θ - 2π = -138341π/584000

θ = 2π + sin^-1(y) = 1029659π/584000

cos^-1(x) = 2π - θ = 138341π/584000

θ = 2π - cos^-1(x) = 1029659π/584000

d. Although you have already done it workout M/(73/6), M and k.

M/(73/6) = θ/2π = 1029659/1168000

M = M/(73/6) × (73/6) = 1029659/96000

k = M - d/30 = 10

e. Although you have already done it from (s), workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds in reverse order.

d/30 = M - k = 69659/96000

d = (M - k) × 30 = 69659/3200

k = d - h/24 = 21

h/24 = d - k = 2459/3200

h = (d - k) × 24 = 7377/400

k = h - m/60 = 18

m/60 = h - k = 177/400

m = (h - k) × 60 = 531/20

k = m - s/60 = 26

s/60 = m - k = 11/20

s = (m - k) × 60 = 33

t = 57624 years 10 months 21 days 18:26:33

e. Choose and workout the magnitudes of T^1, T^-1, T^2 and T^-2?

T^1 = √(A/B) = 10^12 ps

T^-1 = √(B/A) = 10^-12 Ts

T^2 = A/B = 10^24 ps²

T^-2 = B/A = 10^-24 Ts²

g. Workout the values of t, A and B?

t = A/T^1 = y × 31536000 = 1.817258264793 × 10^12 s

A = tT^1 = X × 10^12 × 10^12 = X × 10^24 ps

B = A/T^2 = X × 10^24 / 10^24 = X × 10^0 Ts

h. Check months and days.

y - d/365 = t / 31536000 - d/365 = 57624

d - h/24 = d/365 × 365 - h/24 = 321

h - m/60 = h/24 × 24 - m/60 = 18

m - s/60 = m/60 × 60 - s/60 = 26

s - cs/100 = s/60 × 60 - cs/100 = 33

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below such as y - M/(365/31) and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 1817258264793 / 31536000 - d/365 = 57624

d - h/24 = (57624.8815573630 - 57624) × 365 - h/24 = 321

h - m/60 = (321.7684375 - 321) × 24 - m/60 = 18

m - s/60 = (18.4425 - 18) × 60 - s/60 = 26

s - cs/100 = (26.55 - 26) × 60 - cs/100 = 33

t = 57624 years 321 days 18:26:33
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• TRIGONOMETRY AND RADIANS

When creating your own trigonometry and radians questions know that if we are being lazy and starting from an angle of M/(73/6) and we want particularly pretty maths or simple fractions then θ needs 2 decimal places. Any less and there are 0 seconds, anymore and the seconds are not a nice whole number. However, if you create the question from the ground up, that is starting with a nice whole number for the seconds and building up, then the maths is very beautiful.

However, starting with an angle of M/(73/6) with 2 decimal places means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0 = 60 s, E.G.: 156.40° will result in 60 s.

However, we can start with an angle of M/(73/6) and use 3 decimal places and still have beautiful maths and finish with a whole number for seconds, but the last of the 3 decimal places must always be 5.

For example:

0.00 or X.005 = 60 s, E.G.: 310.005° will result in 18 s.

0.01 or X.Y15 = 36 s, E.G.: 129.615° will result in 54 s.

0.02 or X.Y25 = 12 s, E.G.: 78.925° will result in 30 s.

0.03 or X.Y35 = 48 s, E.G.: 232.435° will result in 6 s.

0.04 or X.Y45 = 24 s, E.G.: 357.745° will result in 42 s.

0.05 or X.Y55 = 60 s, E.G.: 176.855° will result in 18 s.

0.06 or X.Y65 = 36 s, E.G.: 45.165° will result in 54 s.

0.07 or X.Y75 = 12 s, E.G.: 217.975° will result in 30 s.

0.08 or X.Y85 = 48 s, E.G.: 333.285° will result in 6 s.

0.09 or X.Y95 = 24 s, E.G.: 67.895° will result in 42 s.

0.10 or X.Y05 = 60 s, E.G.: 156.405° will result in 18 s.

As you can see having 2 decimals or 3 decimals with the last decimal as 5 goes up alternately by 12 or 6 for seconds. There are 10 values in total for seconds if we are being lazy and starting with an angle of M/(73/6).

For any other whole number for seconds other than the 10 above, we need to start from scratch from the whole number for (s), then divide s/60 then plus k minutes etc. We go up then down or forward and reverse, that is we create the question and then undo it.

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Question 18:

T^1 = √(A/B) = 10^18 as

k = y - M/(73/6) = 57892

sin(M(73/6) × 2π) = -0.5278455119451

cos(M(73/6) × 2π) = -0.8493404002633

a. Workout θ.

b. Workout M/(73/6), M and k.

c. Workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds.

d. What is the total value of y?

e. What are the magnitudes of T^-1, T^2 and T^-2?

f. What are the values of t, A and B?

g. Check the days and months.

Note: to figure out a fraction radian from a decimal radian, divide the decimal radian by 2π then convert the resulting decimal into a fraction.

For example:

0.6471680866395 / 2π = 0.103 = 103/1000

Then multiply the fraction by 2π.

a.

sin^-1(-0.5278455119451) = π - θ = -177π/1000

θ = π - (-177π/1000) = 1177π/1000

cos^-1(-0.8493404002633) = 2π - θ = 823π/1000

θ = 2π - 823π/1000 = 1177π/1000

b.

M/(73/6) = θ/2π = (1177π/1000)/2π = 1177/2000

M = M/(73/6) × (73/6) = 85921/12000

k = M - d/30 = 7

c.

d/30 = M - k = 1921/12000

d = (M - k) × 30 = 1921/400

k = d - h/24 = 4

h/24 = d - k = 321/400

h = (d - k) × 24 = 963/50

k = h - m/60 = 19

m/60 = h - k = 13/50

m = (h - k) × 60 = 78/5

k = m - s/60 = 15

s/60 = m - k = 3/5

s = (m - k) × 60 = 36

t = 57892 years 7 months 4 days 19:15:36

d.

y = k + M/(73/6) = 115785177/2000

e.

T^-1 = √(B/A) = 10^-18 Es

T^2 = A/B = 10^36 as²

T^-2 = B/A = 10^-36 Es²

f.

t = A/T^1 = y × 31536000 = 1.825700670936 × 10^12 s

A = tT^1 = X × 10^12 × 10^18 = X × 10^30 as

B = A/T^2 = X × 10^30 / 10^36 = X × 10^-6 Es

g.

y - d/365 = t / 31536000 - d/365 = 57892

d - h/24 = d/365 × 365 - h/24 = 214

h - m/60 = h/24 × 24 - m/60 = 19

m - s/60 = m/60 × 60 - s/60 = 15

s - cs/100 = s/60 × 60 - cs/100 = 36

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 1825700670936 / 31536000 - d/365 = 57892

d - h/24 = (57892.5885 - 57892) × 365 - h/24 = 214

h - m/60 = (214.802499999278 - 214) × 24 - m/60 = 19

m - s/60 = (19.2599999826634 - 19) × 60 - s/60 = 15

s - cs/100 = (15.5999989598058 - 15) × 60 - cs/100 = 36

t = 57892 years 214 days 19:15:36
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• TRIGONOMETRY AND RADIANS

To create your own trigonometry questions and to save you time, know that θ or (M/(73/6) × 360) should have 2 decimal places. Any less and there are 0 seconds, anymore and the maths is not beautiful.

Note: 2 decimal places this means there are only 5 possible values for seconds (s).

For example:

0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s.

0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s.

0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s.

0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s.

0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s.

0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s.

0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s.

0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s.

0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s.

0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s.

0.10 or X.Y0= 60 s, E.G.: 156.40° will result in 60 s.

Note: the Mathway app makes light work of fractions and radians, also a second scrap piece of paper is recommended.

The following is the formula for attaining θ in the 4 quadrants of the unit circle:

Q1.

sin^-1(y) = θ

cos^-1(x) = θ

Q2.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = θ

Q3.

sin^-1(y) = π - θ therefore θ = π - sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Q4.

sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y)

cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x)

Question 17:

T^1 = √(A/B) = 10^21 zs

k = y - M/(73/6) = 80723

sin(M(73/6) × 2π) = -0.602929541689

cos(M(73/6) × 2π) = -0.79779443953857

a. Workout θ.

b. Workout M/(73/6), M and k.

c. Workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds.

d. What is the total value of y?

e. What are the magnitudes of T^-1, T^2 and T^-2?

f. What are the values of t, A and B?

g. Check the days and months.

Note: to figure out a fraction radian from a decimal radian, divide the decimal radian by 2π then convert the resulting decimal into a fraction.

For example:

0.6471680866395 / 2π = 0.103 = 103/1000

Then multiply the fraction by 2π.

a.

sin^-1(-0.602929541689) = θ - 2π = -103π/500

θ = 2π - 103π/500 = 897π/500

cos^-1(-0.79779443953857) = 2π - θ = 103π/500

θ = 2π - 103π/500 = 897π/500

b.

M/(73/6) = θ/2π = (897π/500)/2π = 897/1000

M = M/(73/6) × (73/6) = 21827/2000

k = M - d/30 = 10

c.

d/30 = M - k = 1827/2000

d = (M - k) × 30 = 5481/200

k = d - h/24 = 27

h/24 = d - k = 81/200

h = (d - k) × 24 = 243/25

k = h - m/60 = 9

m/60 = h - k = 18/25

m = (h - k) × 60 = 216/5

k = m - s/60 = 43

s/60 = m - k = 1/5

s = (m - k) × 60 = 12

t = 80723 years 10 months 27 days 09:43:12

d.

y = k + M/(73/6) = 80723897/1000

e.

T^-1 = √(B/A) = 10^-21 Zs

T^2 = A/B = 10^42 zs²

T^-2 = B/A = 10^-42 Zs²

f.

t = A/T^1 = y × 31536000 = 2.545708815792 × 10^12 s

A = tT^1 = X × 10^12 × 10^21 = X × 10^33 zs

B = A/T^2 = X × 10^33 / 10^42 = X × 10^-9 Zs

g.

y - d/365 = t / 31536000 - d/365 = 80723

d - h/24 = d/365 × 365 - h/24 = 327

h - m/60 = h/24 × 24 - m/60 = 9

m - s/60 = m/60 × 60 - s/60 = 43

s - cs/100 = s/60 × 60 - cs/100 = 12

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 2545708815792 / 31536000 - d/365 = 80723

d - h/24 = (80723.897- 80723) × 365 - h/24 = 327

h - m/60 = (327.40499999898 - 327) × 24 - m/60 = 9

m - s/60 = (9.71999997552484 - 9) × 60 - s/60 = 43

s - cs/100 = (43.1999985314906 - 43) × 60 - cs/100 = 12

t = 80723 years 327 days 09:43:12
TRIGONOMETRY AND RADIANS To create your own trigonometry questions and to save you time, know that θ or (M/(73/6) × 360) should have 2 decimal places. Any less and there are 0 seconds, anymore and the maths is not beautiful. Note: 2 decimal places this means there are only 5 possible values for seconds (s). For example: 0.00 or X.00 = 60 s, E.G.: 310.00° will result in 60 s. 0.01 or X.Y1 = 36 s, E.G.: 129.61° will result in 36 s. 0.02 or X.Y2 = 12 s, E.G.: 78.92° will result in 12 s. 0.03 or X.Y3 = 48 s, E.G.: 232.43° will result in 48 s. 0.04 or X.Y4 = 24 s, E.G.: 357.74° will result in 24 s. 0.05 or X.Y5 = 60 s, E.G.: 176.85° will result in 60 s. 0.06 or X.Y6 = 36 s, E.G.: 45.16° will result in 36 s. 0.07 or X.Y7 = 12 s, E.G.: 217.97° will result in 12 s. 0.08 or X.Y8 = 48 s, E.G.: 333.28° will result in 48 s. 0.09 or X.Y9 = 24 s, E.G.: 67.89° will result in 24 s. 0.10 or X.Y0= 60 s, E.G.: 156.40° will result in 60 s. Note: the Mathway app makes light work of fractions and radians, also a second scrap piece of paper is recommended. QUADRANTS The following is the formula for attaining θ in the 4 quadrants of the unit circle: Q1. sin^-1(y) = θ cos^-1(x) = θ Q2. sin^-1(y) = π - θ therefore θ = π - sin^-1(y) cos^-1(x) = θ Q3. sin^-1(y) = π - θ therefore θ = π - sin^-1(y) cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x) Q4. sin^-1(y) = θ - 2π therefore θ = 2π + sin^-1(y) cos^-1(x) = 2π - θ therefore θ = 2π - cos^-1(x) Question 17: (TRIGONOMETRY AND RADIANS). T^1 = √(A/B) = 10^21 zs k = y - M/(73/6) = 80723 sin(M(73/6) × 2π) = -0.602929541689 cos(M(73/6) × 2π) = -0.79779443953857 a. Workout θ. b. Workout M/(73/6), M and k. c. Workout the other decimal remainders and integers (k) of the days, hours, minutes and seconds. d. What is the total value of y? e. What are the magnitudes of T^-1, T^2 and T^-2? f. What are the values of t, A and B? g. Check the days and months. Note: to figure out a fraction radian from a decimal radian, divide the decimal radian by 2π then convert the resulting decimal into a fraction. For example: 0.6471680866395 / 2π = 0.103 = 103/1000 Then multiply the fraction by 2π. radian = 103π/500 a. sin^-1(-0.602929541689) = θ - 2π = -103π/500 θ = 2π - 103π/500 = 897π/500 cos^-1(-0.79779443953857) = 2π - θ = 103π/500 θ = 2π - 103π/500 = 897π/500 b. M/(73/6) = θ/2π = (897π/500)/2π = 897/1000 M = M/(73/6) × (73/6) = 21827/2000 k = M - d/30 = 10 c. d/30 = M - k = 1827/2000 d = (M - k) × 30 = 5481/200 k = d - h/24 = 27 h/24 = d - k = 81/200 h = (d - k) × 24 = 243/25 k = h - m/60 = 9 m/60 = h - k = 18/25 m = (h - k) × 60 = 216/5 k = m - s/60 = 43 s/60 = m - k = 1/5 s = (m - k) × 60 = 12 t = 80723 years 10 months 27 days 09:43:12 d. y = k + M/(73/6) = 80723897/1000 e. T^-1 = √(B/A) = 10^-21 Zs T^2 = A/B = 10^42 zs² T^-2 = B/A = 10^-42 Zs² f. t = A/T^1 = y × 31536000 = 2.545708815792 × 10^12 s A = tT^1 = X × 10^12 × 10^21 = X × 10^33 zs B = A/T^2 = X × 10^33 / 10^42 = X × 10^-9 Zs g. y - d/365 = t / 31536000 - d/365 = 80723 d - h/24 = d/365 × 365 - h/24 = 327 h - m/60 = h/24 × 24 - m/60 = 9 m - s/60 = m/60 × 60 - s/60 = 43 s - cs/100 = s/60 × 60 - cs/100 = 12 NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator. For example: Note: you do not need to write the below, it is all done on the calculator. y - d/365 = 2545708815792 / 31536000 - d/365 = 80723 d - h/24 = (80723.897- 80723) × 365 - h/24 = 327 h - m/60 = (327.40499999898 - 327) × 24 - m/60 = 9 m - s/60 = (9.71999997552484 - 9) × 60 - s/60 = 43 s - cs/100 = (43.1999985314906 - 43) × 60 - cs/100 = 12 t = 80723 years 327 days 09:43:12
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• Note: if you want to create your own trigonometry questions, to save you time, θ or M/(73/6) × 360 should have at least 2 decimal places, otherwise, there are 0 seconds. And 3 decimal places is recommended as the maximum.

Note: radians are very hard, you basically must have the Mathway app to make light work of fractions and radians, also a second scrap piece of paper is recommended.

Question 16:

T^1 = √(A/B) = 10^12 ps

k = y - M/(73/6) = 81073

sin(M(73/6) × 2π) = -0.9260024197156

cos(M(73/6) × 2π) = -0.3775175740026

a. What are the magnitudes of T^-1, T^2 and T^-2?

b. Workout θ.

c. Workout M/(73/6) and the other decimal remainders and integers (k) of the months, days, hours, minutes and seconds.

d. What is the total value of y?

e. What are the values of t, A and B?

f. Check the days and months.

a.

T^-1 = √(B/A) = 10^-12 Ts

T^2 = A/B = 10^24 ps²

T^-2 = B/A = 10^-24 Ts²

b.

sin^-1(-0.9260024197156) = -3391π/9000

cos^-1(-0.3775175740026) = 5609π/9000

θ = π + 3391π/9000 = 12391π/9000

or

θ = 2π - 5609π/9000 = 12391π/9000

c.

M/(73/6) = (12391π/9000)/2π = 12391/18000

M = M/(73/6) × (73/6) = 904543/108000

k = M - d/30 = 8

d/30 = M - k = 40543/108000

d = (M - k) × 30 = 40543/3000

k = d - h/24 = 11

h/24 = d - k = 943/3600

h = (d - k) × 24 = 943/150

k = h - m/60 = 6

m/60 = h - k = 43/150

m = (h - k) × 60 = 86/5

k = m - s/60 = 17

s/60 = m - k = 1/5

s = (m - k) × 60 = 12

d.

y = k + M/(73/6) = 1459326391/18000

e.

t = A/T^1 = y × 31536000 = 2.556739837032 × 10^12s

A = tT^1 = X × 10^12 × 10^12 = X × 10^24 ps

B = A/T^2 = X × 10^24 / 10^24 = X Ts

f.

y - d/365 = t / 31536000 - d/365 = 81073

d - h/24 = d/365 × 365 - h/24 = 251

h - m/60 = h/24 × 24 - m/60 = 6

m - s/60 = m/60 × 60 - s/60 = 17

s - cs/100 = s/60 × 60 - cs/100 = 12

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y - d/365 = 2556739837032 / 31536000 - d/365 = 81073

d - h/24 = (81073.6883888889 - 81073) × 365 - h/24 = 251

h - m/60 = (251.26194444274 - 251) × 24 - m/60 = 6

m - s/60 = (6.28666662576143 - 6) × 60 - s/60 = 17

s - cs/100 = (17.1999975456856 - 17) × 60 - cs/100 = 12

t = 81073 years 251 days 06:17:12
Note: if you want to create your own trigonometry questions, to save you time, θ or M/(73/6) × 360 should have at least 2 decimal places, otherwise, there are 0 seconds. And 3 decimal places is recommended as the maximum. Note: radians are very hard, you basically must have the Mathway app to make light work of fractions and radians, also a second scrap piece of paper is recommended. Question 16: (TRIGONOMETRY AND RADIANS). T^1 = √(A/B) = 10^12 ps k = y - M/(73/6) = 81073 sin(M(73/6) × 2π) = -0.9260024197156 cos(M(73/6) × 2π) = -0.3775175740026 a. What are the magnitudes of T^-1, T^2 and T^-2? b. Workout θ. c. Workout M/(73/6) and the other decimal remainders and integers (k) of the months, days, hours, minutes and seconds. d. What is the total value of y? e. What are the values of t, A and B? f. Check the days and months. a. T^-1 = √(B/A) = 10^-12 Ts T^2 = A/B = 10^24 ps² T^-2 = B/A = 10^-24 Ts² b. sin^-1(-0.9260024197156) = -3391π/9000 cos^-1(-0.3775175740026) = 5609π/9000 θ = π + 3391π/9000 = 12391π/9000 or θ = 2π - 5609π/9000 = 12391π/9000 c. M/(73/6) = (12391π/9000)/2π = 12391/18000 M = M/(73/6) × (73/6) = 904543/108000 k = M - d/30 = 8 d/30 = M - k = 40543/108000 d = (M - k) × 30 = 40543/3000 k = d - h/24 = 11 h/24 = d - k = 943/3600 h = (d - k) × 24 = 943/150 k = h - m/60 = 6 m/60 = h - k = 43/150 m = (h - k) × 60 = 86/5 k = m - s/60 = 17 s/60 = m - k = 1/5 s = (m - k) × 60 = 12 d. y = k + M/(73/6) = 1459326391/18000 e. t = A/T^1 = y × 31536000 = 2.556739837032 × 10^12s A = tT^1 = X × 10^12 × 10^12 = X × 10^24 ps B = A/T^2 = X × 10^24 / 10^24 = X Ts f. y - d/365 = t / 31536000 - d/365 = 81073 d - h/24 = d/365 × 365 - h/24 = 251 h - m/60 = h/24 × 24 - m/60 = 6 m - s/60 = m/60 × 60 - s/60 = 17 s - cs/100 = s/60 × 60 - cs/100 = 12 NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator. For example: Note: you do not need to write the below, it is all done on the calculator. y - d/365 = 2556739837032 / 31536000 - d/365 = 81073 d - h/24 = (81073.6883888889 - 81073) × 365 - h/24 = 251 h - m/60 = (251.26194444274 - 251) × 24 - m/60 = 6 m - s/60 = (6.28666662576143 - 6) × 60 - s/60 = 17 s - cs/100 = (17.1999975456856 - 17) × 60 - cs/100 = 12 t = 81073 years 251 days 06:17:12
2
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• For the simplest possible example:

t = 1 second

T^1 = 100 cs

T^2 = (1 × 100) / (1 / 100) = 100² = 10000 cs²

A = 1 × 100 = 100 centiseconds (cs)

B = 1 / 100 = 0.01 hectoseconds (hs)

Note how 100, 1 and 0.01 all equal the same length of time.

Equipment.

You need a calculator that converts decimals to fractions to practice mathematics and time. I recommend the Natural Scientific Calculator.

Requirements.

There are just a few very simple things you need to know to practice maths and time. You can learn them all in seconds.

1. Orders of magnitude (time).

https://mathsandtime.com/orders-of-magnitude-time/

As in attosecond (as) and exasecond (Es) etc. The above link is used for quick reference.

2. Scientific notation.

https://www.purplemath.com/modules/exponent3.htm

As in 2.3855886103 × 10^13

X = 2.3855886103

3. Basics rules of exponents.

https://www.purplemath.com/modules/exponent.htm

As in when you multiply two exponents you add the exponents.

X × 10^13 × 10^6 = X × 10^19

And when you divide two exponents you subtract the exponents.

X × 10^6 / 10^13 = X × 10^-7

That is about it!

Question.

An example of a square of time:

(ORDERS OF MAGNITUDE AND EXPONENTS)

B = A/T^2 = X × 10^4 Ms

What are the magnitudes of T^1, T^-1, T^2 and T^-2?

What are the powers n of X × 10^n for A and t?

T^1 = √(A/B) = 10^6 μs

T^-1 = √(B/A) = 10^-6 Ms

T^2 = A/B = 10^12 μs²

T^-2 = B/A = 10^-12 Ms²

A = BT^2 = X × 10^4 × 10^12 = X × 10^16 μs

t = A/T^1 = X × 10^16 / 10^6 = X × 10^10 s

It is an inverse square of time!
For the simplest possible example: t = 1 second T^1 = 100 cs T^2 = (1 × 100) / (1 / 100) = 100² = 10000 cs² A = 1 × 100 = 100 centiseconds (cs) B = 1 / 100 = 0.01 hectoseconds (hs) Note how 100, 1 and 0.01 all equal the same length of time. Equipment. You need a calculator that converts decimals to fractions to practice mathematics and time. I recommend the Natural Scientific Calculator. https://8uvp.app.link/FeZPwAXF1V Requirements. There are just a few very simple things you need to know to practice maths and time. You can learn them all in seconds. 1. Orders of magnitude (time). https://mathsandtime.com/orders-of-magnitude-time/ As in attosecond (as) and exasecond (Es) etc. The above link is used for quick reference. 2. Scientific notation. https://www.purplemath.com/modules/exponent3.htm As in 2.3855886103 × 10^13 X = 2.3855886103 3. Basics rules of exponents. https://www.purplemath.com/modules/exponent.htm As in when you multiply two exponents you add the exponents. X × 10^13 × 10^6 = X × 10^19 And when you divide two exponents you subtract the exponents. X × 10^6 / 10^13 = X × 10^-7 That is about it! Question. An example of a square of time: (ORDERS OF MAGNITUDE AND EXPONENTS) B = A/T^2 = X × 10^4 Ms What are the magnitudes of T^1, T^-1, T^2 and T^-2? What are the powers n of X × 10^n for A and t? Answer: T^1 = √(A/B) = 10^6 μs T^-1 = √(B/A) = 10^-6 Ms T^2 = A/B = 10^12 μs² T^-2 = B/A = 10^-12 Ms² A = BT^2 = X × 10^4 × 10^12 = X × 10^16 μs t = A/T^1 = X × 10^16 / 10^6 = X × 10^10 s It is an inverse square of time!
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• #CommonDenominator
March 26 “For there is #oneGod, and #oneMediator also between #God and men, the man #ChristJesus.” #ITimothy2:5
Listen to #todaysDevotional

How do you add #oneHalf and #oneThird? I’m not sure how they do it in #school these days, but I remember that in order to add these #fractions, we had to find a #commonDenominator. Once you did that, you could #solveTheProblem.

A common Denominator. That’s one way of #explaining the #meaning of the word “ #mediator.” #JesusChrist, who is both God and #man, is the #common #denominator who #solvedTheProblem of how to #reconcile an #infiniteGod with #finiteMan. #Jesus bridged the #gap that #separatedUs from God. He is the #gobetween who brings us to God – and Who makes #peace with God #possible. https://mailchi.mp/winningwalk/the-truest-freedom-you-can-ever-experience-452085?e=9cbe669f39 #therightpath #truth #hiswill #bible #love #faith #dailydevotions #bridging #mindfulness #inspiration #GodHasAPlan #reconcilement #motivationalquote #DailyDevotional #Devotions #Scripture #Quote #GodIsTheWay #TheWay #DoYouKnowTheWay #DoYouKnowDeWay #TheOneTrueGod #TheOnlyGod #LivingGod #AlmightyGod #AmazingGod #reconciliation #Forgiveness #GoodNews #Gospel #TheGospel #Bible #BibleStudy #BibleVerse #godisgood #godisgreat
#CommonDenominator March 26 “For there is #oneGod, and #oneMediator also between #God and men, the man #ChristJesus.” #ITimothy2:5 Listen to #todaysDevotional How do you add #oneHalf and #oneThird? I’m not sure how they do it in #school these days, but I remember that in order to add these #fractions, we had to find a #commonDenominator. Once you did that, you could #solveTheProblem. A common Denominator. That’s one way of #explaining the #meaning of the word “ #mediator.” #JesusChrist, who is both God and #man, is the #common #denominator who #solvedTheProblem of how to #reconcile an #infiniteGod with #finiteMan. #Jesus bridged the #gap that #separatedUs from God. He is the #gobetween who brings us to God – and Who makes #peace with God #possible. https://mailchi.mp/winningwalk/the-truest-freedom-you-can-ever-experience-452085?e=9cbe669f39 #therightpath #truth #hiswill #bible #love #faith #dailydevotions #bridging #mindfulness #inspiration #GodHasAPlan #reconcilement #motivationalquote #DailyDevotional #Devotions #Scripture #Quote #GodIsTheWay #TheWay #DoYouKnowTheWay #DoYouKnowDeWay #TheOneTrueGod #TheOnlyGod #LivingGod #AlmightyGod #AmazingGod #reconciliation #Forgiveness #GoodNews #Gospel #TheGospel #Bible #BibleStudy #BibleVerse #godisgood #godisgreat
Common Denominator
Jesus bridged the gap that separated us from God.
MAILCHI.MP
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• CERN.
(Center of European Nuclear Research)
Really ? think Cernunis, Celtic pagan god
Purpose of CERN – Extreme mass collision – Light particles.
Reason – Higgs/boson – God particle – OR
Open a dimensional portal, are you serious !!!. Actually, yes, scientists now state that there are up to 10 dimensions, crazy hey, but not, you have been lied to all your life, why should they stop lying now.
One year after CERN’s grand opening, Sergio Bertolucci, former Director for Research and Scientific Computing of the facility, grabbed headlines when he told a British tabloid the super collider could open otherworldly doors to another dimension for "a very tiny lapse of time,” mere fractions of a second. However, that may be just enough time “to peer into this open door, either by getting something out of it or sending something into it.”
CERN has been constructed for one purpose and one purpose only, where is it, why was it built there, did you see the dance filmed there, SYMMETRY, or the ceremony when the rail line was completed, if you saw any of these things and were not disquieted, then you are asleep. They openly exalt the worship of ancient pagan gods, so much so that they staged a gala show for them, see the Gotthard Base Tunnel opening.
It is built on the site of the ancient temple to Apollyon, see Revelation (9:1-2, 11), which makes reference to the name ‘Apollyon.’ The verse states: “To him was given the key of the bottomless pit. And he opened the bottomless pit… And they had a king over them, which is the angel of the bottomless pit, whose name in the Hebrew tongue is Abaddon, but in the Greek tongue hath his name Apollyon.”
Now try telling a spiritual leader that the Bible is conspiracy theory.
And why would you erect a statue to shiva, Hindu god of creation and destruction, cancel out the creation, there is only one creator, shiva is actually recognized more for destruction, you should be feeling a bit queezy by now

CERN. (Center of European Nuclear Research) Really ? think Cernunis, Celtic pagan god Purpose of CERN – Extreme mass collision – Light particles. Reason – Higgs/boson – God particle – OR Open a dimensional portal, are you serious !!!. Actually, yes, scientists now state that there are up to 10 dimensions, crazy hey, but not, you have been lied to all your life, why should they stop lying now. One year after CERN’s grand opening, Sergio Bertolucci, former Director for Research and Scientific Computing of the facility, grabbed headlines when he told a British tabloid the super collider could open otherworldly doors to another dimension for "a very tiny lapse of time,” mere fractions of a second. However, that may be just enough time “to peer into this open door, either by getting something out of it or sending something into it.” CERN has been constructed for one purpose and one purpose only, where is it, why was it built there, did you see the dance filmed there, SYMMETRY, or the ceremony when the rail line was completed, if you saw any of these things and were not disquieted, then you are asleep. They openly exalt the worship of ancient pagan gods, so much so that they staged a gala show for them, see the Gotthard Base Tunnel opening. It is built on the site of the ancient temple to Apollyon, see Revelation (9:1-2, 11), which makes reference to the name ‘Apollyon.’ The verse states: “To him was given the key of the bottomless pit. And he opened the bottomless pit… And they had a king over them, which is the angel of the bottomless pit, whose name in the Hebrew tongue is Abaddon, but in the Greek tongue hath his name Apollyon.” Now try telling a spiritual leader that the Bible is conspiracy theory. And why would you erect a statue to shiva, Hindu god of creation and destruction, cancel out the creation, there is only one creator, shiva is actually recognized more for destruction, you should be feeling a bit queezy by now
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